700419. Palindromic Array

Basic

Palindromic Array

Slug: palindric-array-1587115620 Difficulty: Basic Id: 700419 Topic Tags: Arrays, Data Structures Company Tags: None

Summary

Given an array of integers, determine whether the array is a palindrome or not. A palindrome array is one that remains the same when its elements are reversed.

This problem involves working with arrays and determining if they meet specific conditions (in this case, being palindromic). The key concept involved is checking for symmetry in the array by comparing it to its reverse.

Detailed Explanation

To solve this problem, we will use a simple algorithm that compares the original array with its reverse. Here's the step-by-step breakdown:

  1. Create a variable isPalindromic and initialize it to true.
  2. Calculate the reverse of the given array.
  3. Compare each element of the original array with the corresponding element in the reversed array.
  4. If at any point the elements don't match, set isPalindromic to false.
  5. Return the value of isPalindromic.

Here's a diagram illustrating this approach:

  Original Array: [1, 2, 3, 2, 1]
  Reverse Array: [1, 2, 3, 2, 1]

  Compare elements:
    1 == 1 (match)
    2 == 2 (match)
    3 == 3 (match)
    2 == 2 (match)
    1 == 1 (match)

  Since all elements match, the array is palindromic.

Time complexity: O(n), where n is the length of the array. This is because we need to traverse the entire array once.

Space complexity: O(1), as we only use a few extra variables to store the reverse and comparison results.

Optimized Solutions

Java

View on GeeksforGeeks
public boolean isPalindromic(int[] arr) {
    int left = 0;
    int right = arr.length - 1;
    while (left < right) {
        if (arr[left] != arr[right]) {
            return false;
        }
        left++;
        right--;
    }
    return true;
}

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