700828. Count the Specials - Java
Count the Specials - Java
Slug: count-the-specials-java
Difficulty: Easy
Id: 700828
Topic Tags: Arrays, Data Structures
Company Tags: None
Summary
Counting Special Characters is an easy problem that involves counting the number of special characters in a given string. The problem requires you to write a program that takes a string as input and outputs the count of special characters in it.
Detailed Explanation
The algorithm for this problem is quite straightforward. We can iterate over each character in the string and check if it's a special character or not. A special character is typically defined as any character that's not an alphabet (both lowercase and uppercase) or a digit.
Here's a step-by-step breakdown of the solution:
- Initialize a variable
specialCountto 0, which will store the count of special characters. - Iterate over each character in the string using a loop.
- For each character, check if it's a special character by using a conditional statement (e.g.,
if (!Character.isLetterOrDigit(c))). If the character is not a letter or digit, incrementspecialCount. - After the loop, return the value of
specialCountas the result.
The time complexity for this algorithm is O(n), where n is the length of the input string. This is because we're iterating over each character in the string once. The space complexity is O(1), as we're only using a constant amount of space to store the count of special characters.
Optimized Solutions
Java
public int countSpecialChars(String str) {
int specialCount = 0;
for (char c : str.toCharArray()) {
if (!Character.isLetterOrDigit(c)) {
specialCount++;
}
}
return specialCount;
}