702669. Minimum Product of k Integers
Basic
Minimum Product of k Integers
Summary
Given an array of integers, find the minimum product that can be obtained by multiplying k distinct elements from the array. This problem involves arrays and sorting.
Detailed Explanation
The approach to solve this problem is to first sort the array in descending order. Then, multiply the k smallest numbers together to get the minimum product. The reason for choosing the k smallest numbers is that they will give us the maximum product when multiplied together.
Here's a step-by-step breakdown of the solution:
- Sort the array in descending order.
- Initialize a variable
min_productto store the minimum product. - Iterate through the first k elements of the sorted array and multiply them together.
- Update
min_productwith the current product if it's smaller than the previous minimum product.
Time complexity: O(n log n) due to the sorting step where n is the number of elements in the array.
Space complexity: O(1) as we are only using a constant amount of space to store the sorted array and the minimum product.
Optimized Solutions
Java
public class Main {
public static long minProduct(int[] arr, int k) {
Arrays.sort(arr);
long min_product = 1;
for (int i = 0; i < k; i++) {
min_product *= arr[i];
}
return min_product;
}
public static void main(String[] args) {
int[] arr = {10, 20, 30, 40, 50};
int k = 3;
long result = minProduct(arr, k);
System.out.println("Minimum product: " + result);
}
}