702701. Max value

Easy

Max Value

Slug: max-value1205 Difficulty: Easy Id: 702701 Topic Tags: Arrays, Data Structures Company Tags: Amazon

Summary

The problem is about finding the maximum value in an array. The key concepts involved are arrays and data structures.

Detailed Explanation

To solve this problem, we will iterate through the array and keep track of the maximum value seen so far. We can use a variable to store the maximum value and update it whenever we find a larger value in the array.

Here is the step-by-step breakdown of the solution:

  1. Initialize a variable max_value to the first element of the array.
  2. Iterate through the rest of the array.
  3. For each element, check if it is greater than max_value. If it is, update max_value.
  4. After iterating through the entire array, max_value will hold the maximum value in the array.

Here is a simple ASCII art diagram to illustrate the process:

  +--------+
  | 1     |
  +--------+
         ^
  | 2     |
  +--------+
         ^
  | 3     |
  +--------+
         ^
  ...    ...

The time complexity of this solution is O(n), where n is the size of the array. The space complexity is O(1) because we only use a constant amount of space to store max_value.

Optimized Solutions

Java

View on GeeksforGeeks
public int maxValue(int[] arr) {
    int max = arr[0];
    for (int i = 1; i < arr.length; i++) {
        if (arr[i] > max) {
            max = arr[i];
        }
    }
    return max;
}

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