702784. Greedy Fox
Here is the generated blog post:
Greedy Fox
Slug: greedy-fox1555 Difficulty: Easy Id: 702784 Topic Tags: Arrays, Data Structures Company Tags: None
Summary
The Greedy Fox problem involves a given array of integers where each integer represents the number of steps taken by a fox to reach its current position. The task is to find the maximum number of steps the fox can take without getting trapped in a loop.
Detailed Explanation
To solve this problem, we will use a greedy approach. We will iterate through the array and keep track of the maximum number of steps the fox can take at each position. At each step, we will consider the current position and the next position in the array. If the difference between the two positions is greater than or equal to 1, it means that the fox has reached a new peak and can continue moving forward. Otherwise, it means that the fox has reached a loop and cannot move further.
Here's a step-by-step breakdown of the solution:
- Initialize
max_stepsvariable to keep track of the maximum number of steps taken by the fox. - Iterate through the array from left to right.
- At each position, check if the difference between the current position and the next position is greater than or equal to 1.
- If the condition in step 3 is true, increment
max_stepsvariable by 1. - Return
max_stepsas the maximum number of steps the fox can take.
Time complexity: O(n), where n is the size of the input array.
Space complexity: O(1), as we only use a constant amount of space to store the max_steps variable.
Optimized Solutions
Here are the optimized solutions in different programming languages:
Java
public int maxSteps(int[] arr) {
int maxSteps = 0;
for (int i = 1; i < arr.length; i++) {
if (arr[i] - arr[i-1] >= 1) {
maxSteps++;
}
}
return maxSteps;
}