702864. Max Odd Sum
Max Odd Sum
Slug: max-odd-sum0651 Difficulty: Basic Id: 702864 Topic Tags: Arrays, Data Structures Company Tags: None
Summary
The problem is about finding the maximum sum of odd numbers in a given array. The algorithm needs to iterate through the array, identify and add the odd numbers, and then keep track of the maximum sum found so far.
Detailed Explanation
To solve this problem, we can start by initializing two variables: max_sum to store the maximum sum found so far, and current_sum to store the sum of odd numbers encountered. We iterate through the array, checking each element if it's odd or even. If an element is odd, we add it to current_sum. If an element is even, we reset current_sum to 0.
Here's a step-by-step breakdown:
- Initialize
max_sumandcurrent_sum. - Iterate through the array:
- Check each element if it's odd or even.
- If the element is odd, add it to
current_sum. If the element is even, resetcurrent_sumto 0.
- Update
max_sumifcurrent_sumis greater thanmax_sum. - Return
max_sum.
Time complexity: O(n), where n is the length of the array.
Space complexity: O(1), as we only use a constant amount of space to store the variables.
Optimized Solutions
Java
public int maxOddSum(int[] arr) {
int max_sum = 0;
int current_sum = 0;
for (int num : arr) {
if (num % 2 != 0) { // Check if number is odd
current_sum += num;
} else {
current_sum = 0;
}
max_sum = Math.max(max_sum, current_sum);
}
return max_sum;
}