702995. Stuffs Division
Easy
Here is the generated Markdown blog post:
Stuffs Division
Slug: stuffs-division5735
Difficulty: Easy
Id: 702995
Topic Tags: Arrays, Mathematical, Data Structures, Algorithms
Company Tags: None
Summary
The problem "Stuffs Division" involves dividing an array of integers into groups based on certain conditions. The key concepts involved are arrays and mathematical operations.
Detailed Explanation
To solve this problem, we need to iterate through the input array and group the elements based on their remainder when divided by a certain number (let's call it k). We can use a simple loop to achieve this. Here's a step-by-step breakdown of the solution:
- Initialize an empty array
resultto store the grouped elements. - Iterate through the input array
arr. - For each element
xinarr, calculate its remainder when divided bykusing the modulo operator (%). - Use this remainder as an index into
resultand appendxto the corresponding group. - Return the
resultarray.
Here's a sample diagram to illustrate the process:
arr = [3, 6, 9, 12, 15]
k = 3
result = [[3], [6, 9], [12, 15]]
remainder 0: [3]
remainder 1: [6, 9]
remainder 2: [12, 15]
The time complexity of this solution is O(n), where n is the length of the input array. The space complexity is also O(n) since we need to store the grouped elements in the result array.
Optimized Solutions
Java
public int[][] stuffsDivision(int[] arr, int k) {
int n = arr.length;
int[][] result = new int[(n + k - 1) / k][k];
for (int i = 0; i < n; i++) {
result[i % k][i / k] = arr[i];
}
return result;
}