Quick Left Rotation

Slug: quick-left-rotation3806 Difficulty: Basic Id: 703084 Topic Tags: Arrays, Data Structures Company Tags: None

Summary

Given an array of integers and a rotation value k, perform a left rotation on the array by k positions. This means that elements at indices 0 to k-1 should be shifted to the end of the array.

Detailed Explanation

The problem can be solved using a straightforward algorithmic approach. We will create a new array with the same length as the input array and then populate it with the rotated elements.

Here's the step-by-step breakdown:

1. Create an empty array result with the same length as the input array.
2. Iterate from index k to the end of the input array, inclusive. For each element at index i, place it at the beginning of the result array (at index (i-k)%n, where n is the length of the input array).
3. Copy the remaining elements from the input array (from index 0 to k-1) to the end of the result array.

Here's an ASCII art diagram illustrating the rotation:

Input: [1, 2, 3, 4, 5]
Rotation: 2
Result: [3, 4, 5, 1, 2]

Time complexity analysis:

• The algorithm iterates through the input array once, so the time complexity is O(n), where n is the length of the input array.

Space complexity analysis:

• We create a new array to store the rotated elements, which has the same length as the input array. Therefore, the space complexity is O(n).

Optimized Solutions

Java