703088. Bitonic Generator Sort

Easy

Here is a detailed Markdown blog post for the GeeksforGeeks problem "Bitonic Generator Sort":

Bitonic Generator Sort

Summary

The Bitonic Generator Sort problem involves sorting an array using the bitonic sort algorithm, which is based on the concept of merging and distributing. The goal is to arrange elements in such a way that all elements less than or equal to a certain pivot value are placed before it, while all elements greater than the pivot are placed after it.

Detailed Explanation

The Bitonic Generator Sort algorithm can be broken down into three main steps: generating a bitonic sequence, comparing and distributing, and finalizing the sorting. Here's a step-by-step explanation of each step:

  1. Generating a Bitonic Sequence: The first step is to generate a bitonic sequence, which is an array that alternates between ascending and descending order. This is achieved by iterating through the array and swapping adjacent elements if they are in the wrong order.

Example:

Input: [5, 2, 8, 3, 1, 6, 4]
Bitonic Sequence: [1, 2, 3, 8, 4, 5, 6]
  1. Comparing and Distributing: The second step is to compare the elements in the bitonic sequence and distribute them accordingly. This involves comparing adjacent elements and swapping them if they are out of order.

Example:

Bitonic Sequence: [1, 2, 3, 8, 4, 5, 6]
Distributed Bitonic Sequence: [1, 2, 3] [8, 4, 5] [6]
  1. Finalizing the Sorting: The final step is to finalize the sorting by merging the distributed bitonic sequence into a single sorted array.

Example:

Distributed Bitonic Sequence: [1, 2, 3] [8, 4, 5] [6]
Sorted Array: [1, 2, 3, 4, 5, 6, 8]

Time complexity analysis:

  • Generating a bitonic sequence: O(n)
  • Comparing and distributing: O(n)
  • Finalizing the sorting: O(1)

Space complexity: O(1)

Optimized Solutions

Java

View on GeeksforGeeks
public static void bitonicGeneratorSort(int[] arr) {
    int n = arr.length;
    for (int i = 0; i < n; i++) {
        for (int j = 0; j < n - i - 1; j++) {
            if ((arr[j] > arr[j + 1]) ^ (i % 2 == 0)) {
                int temp = arr[j];
                arr[j] = arr[j + 1];
                arr[j + 1] = temp;
            }
        }
    }
}

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