703181. Rope Cutting

Easy

Here is a detailed Markdown blog post for the Rope Cutting problem:

Rope Cutting

Summary

The Rope Cutting problem involves cutting a rope into small pieces of equal length, given that each piece must be at least 1 unit long. The goal is to maximize the number of pieces obtained by minimizing waste. This problem requires a combination of array manipulation and sorting techniques.

Detailed Explanation

To solve this problem, we can approach it as follows:

  • Initialize an empty array pieces to store the lengths of the cut pieces.
  • Iterate through the rope's length, incrementing the current piece's length until it reaches the maximum allowed piece size (1 unit).
  • Add the current piece's length to the pieces array and reset the current piece's length to 1.
  • Repeat step 2-3 until the rope is fully cut.
  • Sort the pieces array in descending order based on their lengths.

This approach ensures that we minimize waste by cutting pieces of equal length, while also maximizing the number of pieces obtained. The time complexity for this solution is O(n log n) due to the sorting operation, where n is the rope's length. The space complexity is O(n) as we need to store all the piece lengths in the pieces array.

Here's a step-by-step breakdown of the solution:

  1. Initialize an empty array pieces.
  2. Iterate through the rope's length:
    • Increment the current piece's length until it reaches the maximum allowed piece size (1 unit).
    • Add the current piece's length to the pieces array and reset the current piece's length to 1.
  3. Repeat step 2 until the rope is fully cut.
  4. Sort the pieces array in descending order based on their lengths.

Optimized Solutions

Java

View on GeeksforGeeks
public class RopeCutting {
    public static int maxPieces(int n) {
        int pieces = 0;
        for (int i = 1; i <= n; i++) {
            if (n % i == 0) {
                pieces += n / i;
                break;
            }
        }
        return pieces;
    }
}

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