703206. Display longest name
Basic
Display Longest Name
Summary
Given an array of names, find and display the longest name. The problem requires understanding arrays and strings.
Detailed Explanation
The approach to this problem is straightforward: iterate through the array of names, compare the length of each name, and store the longest one. Here's a step-by-step breakdown:
- Initialize a variable
longest_nameto store the longest name found so far. - Iterate through the array of names using a for loop or any other suitable iteration method.
- For each name in the array:
- Calculate its length using the
length()function (in languages that support it) or by manually counting characters. - Compare the length of the current name with the length of the longest name found so far (
longest_name). - If the current name is longer, update
longest_nameto be the current name.
- Calculate its length using the
- After iterating through all names, display the longest name found.
Time and Space Complexity
The time complexity of this algorithm is O(n), where n is the number of names in the array, since we need to iterate through each name once. The space complexity is O(1) because we only use a constant amount of space to store the longest name found.
Optimized Solutions
Java
public class DisplayLongestName {
public static void main(String[] args) {
String[] names = {"John", "Jane", "Jim", "Jessica"};
String longest_name = "";
for (String name : names) {
if (name.length() > longest_name.length()) {
longest_name = name;
}
}
System.out.println("The longest name is: " + longest_name);
}
}