703225. Save Winterfell
Here is a detailed Markdown blog post for the "Save Winterfell" problem:
Save Winterfell
Slug: save-winterfell1447 Difficulty: Medium Id: 703225 Topic Tags: Mathematical, Algorithms Company Tags: None
Summary
The Winterfell kingdom is in danger. A dragon is approaching the castle and will destroy it if it's not saved within a certain time frame. The king has a list of wizards who can help save the kingdom, but they are located at different distances from the castle. Each wizard has a specific distance he or she can travel to help save the kingdom. Your task is to find out which wizard can save the kingdom in the least amount of time.
Detailed Explanation
To solve this problem, we need to iterate over each wizard and check if they can reach Winterfell before the dragon does. We keep track of the minimum distance required to save the kingdom. Here's a step-by-step breakdown of the solution:
- Initialize
min_distanceto infinity. - Iterate over each wizard:
- Calculate the distance from the wizard's location to Winterfell.
- Check if this distance is less than or equal to
min_distance. - If it is, update
min_distancewith this new value.
- Return
min_distance, which is the minimum time required to save the kingdom.
Here's an ASCII art diagram illustrating the problem:
+---------------+
| Wizard A |
| (distance: 3) |
+---------------+
| Wizard B |
| (distance: 5) |
+---------------+
| ... |
+---------------+
| Winterfell |
| (target) |
+---------------+
Time complexity: O(n), where n is the number of wizards. Space complexity: O(1).
Optimized Solutions
Java
public int saveWinterfell(int[] wizardDistances) {
int minDistance = Integer.MAX_VALUE;
for (int distance : wizardDistances) {
if (distance <= minDistance) {
minDistance = distance;
}
}
return minDistance;
}