703463. Sorting all array elements except one
Here is the detailed Markdown blog post for the problem "Sorting all array elements except one":
Sorting all array elements except one
Summary
This problem requires sorting all elements in an array except one, which remains at its original position. This problem involves arrays and sorting concepts.
Detailed Explanation
To solve this problem, we can use a simple sorting algorithm like Bubble Sort or Selection Sort. The key idea is to keep the element that should not be moved from its original position. We will sort all other elements in the array except for one specified index.
Here's the step-by-step breakdown of the solution:
- Identify the index of the element that should remain at its original position.
- Iterate through the array, comparing adjacent elements and swapping them if they are in the wrong order.
- Continue this process until no more swaps are needed, which means the array is sorted except for one element.
Here's an example:
Original Array: [5, 2, 9, 1, 7] Index to remain at its original position: 2
Sorted Array (except one): [1, 2, 4, 7, 9]
The time complexity of this solution is O(n^2) and the space complexity is O(1), where n is the number of elements in the array.
Optimized Solutions
Java
public class Main {
public static void sortExceptOne(int[] arr, int index) {
for (int i = 0; i < arr.length; i++) {
if (i != index) {
for (int j = i + 1; j < arr.length; j++) {
if (arr[i] > arr[j]) {
int temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
}
}
}
}
public static void main(String[] args) {
int[] arr = {5, 2, 9, 1, 7};
int index = 2;
sortExceptOne(arr, index);
for (int i : arr) {
System.out.print(i + " ");
}
}
}