703867. Longest Increasing Subarray
Here is a detailed Markdown blog post for the "Longest Increasing Subarray" problem:
Longest Increasing Subarray
Slug: longest-increasing-subarray3811
Difficulty: Basic
Id: 703867
Topic Tags: Arrays, Data Structures
Company Tags: Amazon
Summary
Given an array of integers, find the length of the longest increasing subarray. An increasing subarray is a sequence of elements where each element is greater than its previous one.
This problem requires you to understand arrays and data structures, as well as basic algorithmic concepts like loops and conditional statements.
Detailed Explanation
To solve this problem, we can start by iterating through the array and keeping track of the length of the longest increasing subarray ending at each position. We do this by maintaining a variable max_length to keep track of the maximum length found so far, and another variable current_length to keep track of the length of the current increasing subarray.
Here's the step-by-step breakdown:
- Initialize
max_lengthto 1 (since a single element is always an increasing subarray) andcurrent_lengthto 1. - Iterate through the array, starting from the second element (index 1).
- For each element, check if it is greater than its previous one. If it is, increment
current_length. - If the current element is not greater than its previous one, update
max_lengthto be the maximum ofmax_lengthandcurrent_length, and resetcurrent_lengthto 1. - Continue iterating until the end of the array.
- Return
max_lengthas the length of the longest increasing subarray.
Here's a simple ASCII art diagram illustrating this process:
1 2 3 4 5 6
^-----^-----^
length: 3, max_length: 3
^-----^
length: 2, max_length: 3
^-----^
length: 1, max_length: 3
^-----^
length: 1, max_length: 4
^-----^
length: 1, max_length: 5
Time complexity: O(n), where n is the length of the array. We only need to iterate through the array once. Space complexity: O(1), since we only use a few variables to keep track of our progress.
Optimized Solutions
Java
public int longestIncreasingSubarray(int[] arr) {
int max_length = 1;
int current_length = 1;
for (int i = 1; i < arr.length; i++) {
if (arr[i] > arr[i - 1]) {
current_length++;
} else {
max_length = Math.max(max_length, current_length);
current_length = 1;
}
}
return Math.max(max_length, current_length);
}