713134. Bird and maximum fruit gathering
Bird and maximum fruit gathering
Summary
In this problem, we are given an array of integers representing the positions of fruits on a tree. The task is to maximize the number of fruits that can be gathered by a bird starting from any node in the tree.
The key concepts involved include arrays and data structures, which is reflected in the tags "Arrays" and "Data Structures".
Detailed Explanation
The problem involves finding the maximum number of fruits that can be gathered by a bird. To solve this, we will use a greedy approach to always choose the fruit that is closest to the current position.
Here's the step-by-step breakdown:
- Initialize two variables:
max_fruitsto keep track of the maximum number of fruits andcurrent_positionto keep track of the current position. - Iterate over the array of fruit positions in ascending order.
- For each fruit, calculate the distance between the current fruit and the previous one (if it exists). If this distance is greater than 1, update
max_fruitsto be the maximum of its current value and the number of fruits that can be gathered at this point. - Return
max_fruits.
Here's a diagram illustrating the process:
0 | 2 | 3 | 5 | 6
---------
F1 | | | F2 | F3
| | F4 |
| F5 |
The time complexity of this solution is O(n), where n is the number of fruits, since we iterate over the array once. The space complexity is O(1) as we only use a constant amount of space to store our variables.
Optimized Solutions
Java
int maxFruits(int[] positions) {
int max_fruits = 0;
int current_position = 0;
for (int i = 0; i < positions.length; i++) {
if (positions[i] - current_position > 1) {
max_fruits = Math.max(max_fruits, i);
}
current_position = positions[i];
}
return max_fruits;
}