714166. Maximum Length
Maximum Length
Slug: maximum-length--170647 Difficulty: Medium Id: 714166 Topic Tags: Strings, Data Structures Company Tags: None
Summary
Given a string, we need to find the maximum length of any substring that has at least one repeated character. This problem involves working with strings and data structures.
Detailed Explanation
To solve this problem, we can use a simple algorithm. We iterate through the string and for each character, we check if it is already present in our current substring (or window). If it is not, we add it to the substring and update our maximum length. If it is already present, we update our maximum length accordingly.
Here's a step-by-step breakdown of the solution:
- Initialize an empty string
max_strand an integermax_lenset to 0. - Iterate through the input string
s. - For each character
cins, check if it is already present inmax_str. If not, add it tomax_strand updatemax_lenaccordingly. - Update
max_lenwhenever a repeated character is found. - Return
max_len.
Time complexity: O(n), where n is the length of the input string.
Space complexity: O(1), since we only need a constant amount of space to store our maximum substring and its length.
Optimized Solutions
Here are some optimized solutions in various programming languages:
Java
public int maximumLength(String s) {
if (s == null || s.length() == 0) {
return 0;
}
int max_len = 0;
String max_str = "";
for (int i = 0; i < s.length(); i++) {
boolean found = false;
for (int j = i + 1; j <= s.length(); j++) {
if (s.substring(i, j).contains(String.valueOf(s.charAt(j - 1)))) {
found = true;
break;
}
}
if (!found) {
max_len = Math.max(max_len, j - i);
max_str = s.substring(i, j);
}
}
return max_len;
}