714323. Binary Modulo

Easy

Binary Modulo

Slug: binary-modulo--170648 Difficulty: Easy Id: 714323 Topic Tags: Mathematical, Bit Magic Company Tags: None

Summary

The Binary Modulo problem is an easy-level mathematical problem that requires you to find the remainder of a large number when divided by another number. The key concept involved here is bit manipulation, which helps in solving this problem efficiently.

Detailed Explanation

To solve this problem, we will use bit manipulation techniques. Given two numbers n and m, our task is to find the remainder of n when divided by m. We can do this by using bitwise operators. Here's a step-by-step breakdown of the solution:

  1. Calculate the number of bits required to represent m.
  2. Use bitwise AND operation (&) to get the least significant bit (LSB) of m. This is because we are interested in finding the remainder at the LSB level.
  3. If the LSB of m is 1, then the remainder will be equal to n & m.
  4. If the LSB of m is 0, then the remainder will be equal to n.

Here's an example:

Let n = 17 and m = 5. The binary representation of these numbers are 10101 (17) and 0101 (5).

To find the remainder, we need to perform bitwise AND operation (&) between n and m, which gives us 00001.

So, the remainder is 1.

Time Complexity: O(1) Space Complexity: O(1)

Optimized Solutions

Java

View on GeeksforGeeks
public class Main {
    public static int binaryModulo(int n, int m) {
        return n & m;
    }

    public static void main(String[] args) {
        int n = 17;
        int m = 5;
        System.out.println("The remainder is: " + binaryModulo(n, m));
    }
}

DevExCode

Master coding interviews with Leetcode, system design, TechBit, QuickLearn, DevTips, Tech Battles, and career services.

© 2026 DevExCode. All rights reserved.