878910. Divisor
Divisor
Summary
The problem is about finding all divisors of a given integer. This involves identifying the numbers that can be divided by the original number without leaving a remainder.
Detailed Explanation
The algorithmic approach to this problem is simple: iterate from 1 to the input number and check if the current number is a divisor. A divisor is defined as an integer that divides the original number without leaving a remainder. We can use the modulo operator (%) to perform this check efficiently.
Here's a step-by-step breakdown of the solution:
- Initialize an empty list or array to store the divisors.
- Iterate from 1 to the input number
n. - For each iteration, check if the current number
iis a divisor by checking ifn % i == 0. If it is, addito the list of divisors. - Return the list of divisors.
Time complexity: O(n), where n is the input number. This is because we iterate from 1 to n and perform a constant-time operation (checking for divisibility) at each iteration.
Space complexity: O(1), as we only use a constant amount of space to store the list of divisors.
Optimized Solutions
Java
public List<Integer> findDivisors(int n) {
List<Integer> divisors = new ArrayList<>();
for (int i = 1; i <= n; i++) {
if (n % i == 0) {
divisors.add(i);
}
}
return divisors;
}