884375. Number of times graph cuts X-axis
Number of times graph cuts X-axis
Summary
Given a set of points (x, y) in a 2D plane, find out how many times the graph formed by these points cuts the x-axis. The graph is considered to cut the x-axis when a point's y-coordinate changes sign from negative to positive.
Detailed Explanation
The problem can be solved using a simple algorithm that iterates through the set of points and checks if the current point's y-coordinate has changed sign compared to the previous one. If it has, increment a counter to keep track of how many times the graph cuts the x-axis.
Here is a step-by-step breakdown of the solution:
- Initialize a variable
cutsto 0, which will store the number of times the graph cuts the x-axis. - Iterate through the set of points (x, y).
- For each point, check if the current point's y-coordinate has changed sign compared to the previous one. This can be done by checking if
y * prev_yis negative or positive. - If the sign has changed, increment the
cutsvariable. - Update the
prev_yvariable with the current point's y-coordinate.
Time complexity: O(n), where n is the number of points in the set.
Space complexity: O(1), as we only use a constant amount of space to store the cuts and prev_y variables.
Here is an ASCII art diagram illustrating the problem:
+-----------------------+
| (0, -5) |
| +---------------+ |
| | | |
| | (-2, -3) | |
| | | |
| +---------------+ |
| (1, 2) |
| +---------------+ |
| | | |
| | (2, 4) | |
| | | |
| +---------------+ |
+-----------------------+
Optimized Solutions
Java
public int countCuts(int[][] points) {
int cuts = 0;
double prev_y = Double.NEGATIVE_INFINITY;
for (int[] point : points) {
if ((point[1] * prev_y) < 0) {
cuts++;
}
prev_y = point[1];
}
return cuts;
}