LeetCode 1010: Pairs of Songs With Total Durations Divisible by 60 Solution

Master LeetCode problem 1010 (Pairs of Songs With Total Durations Divisible by 60), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1010. Pairs of Songs With Total Durations Divisible by 60

Medium

Array Hash Table Counting

Problem Explanation

Explanation

To solve this problem, we can utilize the concept of remainders and modular arithmetic. We can iterate through the given list of song durations and calculate the remainder when divided by 60. Then, we can count the number of pairs that sum up to a multiple of 60.

We can create a frequency array to store the frequency of remainders encountered so far. For each song duration, we can calculate its remainder when divided by 60. Then, we can check how many other songs can form a pair with it to make the total duration divisible by 60.

Solution Code

class Solution {
    public int numPairsDivisibleBy60(int[] time) {
        int[] count = new int[60];
        int pairs = 0;
        
        for (int t : time) {
            int remainder = t % 60;
            int complement = (60 - remainder) % 60;
            
            pairs += count[complement];
            count[remainder]++;
        }
        
        return pairs;
    }
}

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