LeetCode 1017: Convert to Base -2 Solution
Master LeetCode problem 1017 (Convert to Base -2), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1017. Convert to Base -2
Problem Explanation
Explanation
To convert a number to base -2, we can use the idea of binary representation. We can repeatedly divide the number by -2 and keep track of the remainder. The remainder will be either 0 or 1. If the remainder is negative, we need to add 2 to it and update the number as well. This process continues until the number becomes 0. Then, the remainders in reverse order will give us the base -2 representation of the number.
- Time complexity: O(log n) where n is the input number
- Space complexity: O(log n) to store the remainders
Solution Code
class Solution {
public String baseNeg2(int n) {
if (n == 0) return "0";
StringBuilder sb = new StringBuilder();
while (n != 0) {
int remainder = n % -2;
n /= -2;
if (remainder < 0) {
remainder += 2;
n += 1;
}
sb.append(remainder);
}
return sb.reverse().toString();
}
}Try It Yourself
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