LeetCode 1025: Divisor Game Solution
Master LeetCode problem 1025 (Divisor Game), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1025. Divisor Game
Problem Explanation
Explanation
To solve this problem, we can observe that the game results in a win for Alice if the number n is even. This is because regardless of the move Bob makes, Alice can always choose an x that is odd, resulting in an even number for the next turn. Since Bob can only choose odd divisors of an even number, he will eventually end up with an odd number which Alice can then choose an odd divisor for, bringing it back to an even number.
Therefore, the algorithm consists of a simple check to see if n is even. If n is even, Alice wins; otherwise, Bob wins.
- Time complexity: O(1) as it only involves a simple check.
- Space complexity: O(1) as no extra space is used.
Solution Code
class Solution {
public boolean divisorGame(int n) {
return n % 2 == 0;
}
}Try It Yourself
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