LeetCode 1058: Minimize Rounding Error to Meet Target Solution
Master LeetCode problem 1058 (Minimize Rounding Error to Meet Target), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation:
The problem asks to minimize the rounding error between the sum of prices and the target value. We need to round each price to the nearest integer and then calculate the total rounding error. If the total rounded price is less than the target, we can increase some prices to meet the target. We need to minimize the total rounding error.
To solve this problem, we can follow these steps:
- Sort the prices and calculate the total sum of the rounded prices.
- If the rounded sum is less than the target, calculate the remaining amount needed to reach the target.
- Distribute this remaining amount among the prices with fractional parts, by choosing the prices with the smallest fractional parts and increasing them by 1.
- Calculate the total rounding error by summing up the differences between the rounded prices and the original prices.
Solution Code
class Solution {
public String minimizeError(String[] prices, int target) {
double[] errors = new double[prices.length];
double lowerBound = 0.0, upperBound = 0.0;
int sum = 0;
for (int i = 0; i < prices.length; i++) {
double price = Double.parseDouble(prices[i]);
int floor = (int) Math.floor(price);
int ceil = (int) Math.ceil(price);
lowerBound += floor;
upperBound += ceil;
sum += floor;
errors[i] = price - floor;
}
if (target < sum || target > sum + prices.length) {
return "-1";
}
Arrays.sort(errors);
int remaining = target - sum;
int index = 0;
for (int i = 0; i < remaining; i++) {
if (errors[i] > 0) {
lowerBound += 1 - errors[i];
upperBound += 1 - errors[i];
} else {
lowerBound += errors[i];
}
}
return String.format("%.3f", upperBound - target) + "/" + String.format("%.3f", target - lowerBound);
}
}Try It Yourself
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