LeetCode 1072: Flip Columns For Maximum Number of Equal Rows Solution
Master LeetCode problem 1072 (Flip Columns For Maximum Number of Equal Rows), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1072. Flip Columns For Maximum Number of Equal Rows
Problem Explanation
Explanation
- Algorithmic Idea: We need to find the maximum number of rows that have all values equal after some number of flips. We can achieve this by iterating over all possible flips and counting the number of rows with all equal values.
- Start by iterating through all possible columns to flip.
- For each column, flip the values and count the number of rows with all equal values.
- Keep track of the maximum count of rows with all equal values.
- Return the maximum count found.
- Time Complexity: O(m * n^2) where m is the number of rows and n is the number of columns.
- Space Complexity: O(m) where m is the number of rows.
Solution Code
class Solution {
public int maxEqualRowsAfterFlips(int[][] matrix) {
int maxCount = 0;
for (int i = 0; i < matrix.length; i++) {
int count = 0;
int[] target = Arrays.copyOf(matrix[i], matrix[i].length);
for (int j = 0; j < matrix.length; j++) {
int[] temp = Arrays.copyOf(matrix[j], matrix[j].length);
int flip = temp[0] ^ temp[i];
for (int k = 0; k < temp.length; k++) {
temp[k] ^= flip;
}
if (Arrays.equals(temp, target)) {
count++;
}
}
maxCount = Math.max(maxCount, count);
}
return maxCount;
}
}Try It Yourself
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