LeetCode 1085: Sum of Digits in the Minimum Number Solution
Master LeetCode problem 1085 (Sum of Digits in the Minimum Number), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation:
To solve this problem, we need to find the minimum number in a given array, calculate the sum of its digits, and return whether the sum is even or odd.
Algorithmic Idea:
- Iterate through the array to find the minimum number.
- Calculate the sum of digits of the minimum number.
- Check if the sum is even or odd.
Time Complexity:
The time complexity of this solution is O(n), where n is the number of elements in the input array.
Space Complexity:
The space complexity of this solution is O(1) as we are using only a constant amount of extra space.
:
Solution Code
class Solution {
public int sumOfDigits(int[] A) {
int min = A[0];
for (int num : A) {
min = Math.min(min, num);
}
int sum = 0;
while (min > 0) {
sum += min % 10;
min /= 10;
}
return (sum % 2 == 0) ? 1 : 0;
}
}Try It Yourself
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Frequently Asked Questions
How to solve LeetCode 1085 (Sum of Digits in the Minimum Number)?
This page provides optimized solutions for LeetCode problem 1085 (Sum of Digits in the Minimum Number) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.
What is the time complexity of LeetCode 1085 (Sum of Digits in the Minimum Number)?
The time complexity for LeetCode 1085 (Sum of Digits in the Minimum Number) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.
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