LeetCode 1144: Decrease Elements To Make Array Zigzag Solution
Master LeetCode problem 1144 (Decrease Elements To Make Array Zigzag), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation:
To transform the given array into a zigzag array, we need to ensure that each element at an even index is larger than its adjacent elements or each element at an odd index is larger than its adjacent elements. We can achieve this by adjusting the values of the elements in the array downwards.
The algorithm involves iterating through the array and comparing each element with its neighboring elements to determine the number of moves needed to make it satisfy the zigzag condition. We consider two cases: one where we assume the even indices need to be larger and the other where we assume the odd indices need to be larger. We calculate the number of moves needed for each case and return the minimum of the two.
Time Complexity: O(n) where n is the number of elements in the array. Space Complexity: O(1)
:
Solution Code
class Solution {
public int movesToMakeZigzag(int[] nums) {
int n = nums.length;
int even = 0, odd = 0;
for (int i = 0; i < n; i++) {
int left = i > 0 ? nums[i - 1] : Integer.MAX_VALUE;
int right = i < n - 1 ? nums[i + 1] : Integer.MAX_VALUE;
int target = Math.min(left, right) - 1;
if (i % 2 == 0) {
even += Math.max(0, nums[i] - target);
} else {
odd += Math.max(0, nums[i] - target);
}
}
return Math.min(even, odd);
}
}Try It Yourself
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