LeetCode 1189: Maximum Number of Balloons Solution

Master LeetCode problem 1189 (Maximum Number of Balloons), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1189. Maximum Number of Balloons

Easy

Hash Table String Counting

Problem Explanation

Explanation

To solve this problem, we need to count the frequency of each character in the given text. The word "balloon" consists of characters 'b', 'a', 'l', 'o', 'n'. We need to find the minimum frequency of these characters in the text in order to form the maximum number of instances of the word "balloon".

Initialize variables to store the frequencies of 'b', 'a', 'l', 'o', 'n' in the text.
Iterate over the text and count the frequencies of these characters.
Calculate the maximum number of instances of "balloon" that can be formed using the frequencies of these characters.
Return the maximum number of instances.

Time Complexity: O(n) where n is the length of the input text. Space Complexity: O(1) since we are using a constant amount of extra space.

Solution Code

class Solution {
    public int maxNumberOfBalloons(String text) {
        int[] freq = new int[26];
        for (char c : text.toCharArray()) {
            freq[c - 'a']++;
        }

        int minFreq = Math.min(freq['b' - 'a'], Math.min(freq['a' - 'a'], Math.min(freq['l' - 'a'] / 2, Math.min(freq['o' - 'a'] / 2, freq['n' - 'a']))));
        
        return minFreq;
    }
}

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