LeetCode 1221: Split a String in Balanced Strings Solution

Master LeetCode problem 1221 (Split a String in Balanced Strings), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1221. Split a String in Balanced Strings

Easy

String Greedy Counting

Problem Explanation

Explanation

To solve this problem, we can iterate through the given balanced string s and maintain a count of balanced substrings. We can increment the count whenever we encounter an 'L' and decrement the count whenever we encounter an 'R'. The idea is to split the string whenever the count reaches zero, indicating a balanced substring.

Time Complexity

The time complexity of this algorithm is O(n), where n is the length of the input string s.

Space Complexity

The space complexity of this algorithm is O(1) since we are using a constant amount of extra space.

Solution Code

class Solution {
    public int balancedStringSplit(String s) {
        int count = 0;
        int result = 0;
        
        for (char c : s.toCharArray()) {
            if (c == 'L') {
                count++;
            } else {
                count--;
            }
            
            if (count == 0) {
                result++;
            }
        }
        
        return result;
    }
}

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