LeetCode 1243: Array Transformation Solution

Master LeetCode problem 1243 (Array Transformation), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1243. Array Transformation

Problem Explanation

Explanation:

Given an array arr, the task is to transform the array into a strictly increasing sequence by performing a series of operations. Each operation consists of choosing any element arr[i] and incrementing it by 1.

To achieve the transformation, we can iterate through the array from left to right and check if the current element is less than or equal to the previous element. If it is, we increment the current element to make it strictly greater than the previous element.

This approach ensures that the array is transformed into a strictly increasing sequence.

Time Complexity: O(n), where n is the number of elements in the input array Space Complexity: O(1)

: :

Solution Code

class Solution {
    public List<Integer> transformArray(int[] arr) {
        boolean changed;
        do {
            changed = false;
            for (int i = 1; i < arr.length - 1; i++) {
                if (arr[i] <= arr[i - 1] && arr[i] <= arr[i + 1]) {
                    arr[i]++;
                    changed = true;
                } else if (arr[i] >= arr[i - 1] && arr[i] >= arr[i + 1]) {
                    arr[i]--;
                    changed = true;
                }
            }
        } while (changed);
        
        List<Integer> result = new ArrayList<>();
        for (int num : arr) {
            result.add(num);
        }
        return result;
    }
}

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