LeetCode 1255: Maximum Score Words Formed by Letters Solution
Master LeetCode problem 1255 (Maximum Score Words Formed by Letters), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1255. Maximum Score Words Formed by Letters
Problem Explanation
Explanation:
To solve this problem, we can use a brute force approach with backtracking. We will iterate through all possible subsets of words, checking if we can form each subset using the given letters. For each valid subset, we calculate the score and keep track of the maximum score found so far.
Algorithm:
- Create a frequency map of the available letters.
- Generate all possible subsets of words.
- For each subset:
- Check if we can form the subset using the available letters.
- If we can, calculate the score of the subset and update the maximum score if needed.
- Return the maximum score found.
Time Complexity:
The time complexity of this approach is O(2^N) where N is the number of words in the input list.
Space Complexity:
The space complexity is O(1) for the frequency map and O(N) for the recursion stack. :
Solution Code
class Solution {
public int maxScoreWords(String[] words, char[] letters, int[] score) {
int[] letterFreq = new int[26];
for (char c : letters) {
letterFreq[c - 'a']++;
}
return backtrack(words, letterFreq, score, 0);
}
private int backtrack(String[] words, int[] letterFreq, int[] score, int index) {
if (index == words.length) {
return 0;
}
int scoreWithout = backtrack(words, letterFreq.clone(), score, index + 1);
int scoreWith = 0;
String word = words[index];
boolean valid = true;
for (char c : word.toCharArray()) {
if (letterFreq[c - 'a'] == 0) {
valid = false;
}
letterFreq[c - 'a']--;
scoreWith += score[c - 'a'];
}
if (valid) {
scoreWith += backtrack(words, letterFreq, score, index + 1);
}
return Math.max(scoreWith, scoreWithout);
}
}Try It Yourself
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