LeetCode 1266: Minimum Time Visiting All Points Solution

Master LeetCode problem 1266 (Minimum Time Visiting All Points), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1266. Minimum Time Visiting All Points

Problem Explanation

Explanation

To find the minimum time to visit all points in the given order, we can calculate the time taken to move from one point to another by considering the maximum of the absolute differences between the x and y coordinates of consecutive points. This is because we can move diagonally whenever we have to make both x and y coordinate changes.

The time taken to move from one point to another is given by the maximum of the absolute differences in their x and y coordinates. Hence, the total time taken will be the sum of these maximum differences for each pair of consecutive points.

The time complexity of this approach is O(n) where n is the number of points, and the space complexity is O(1) as we are not using any extra space.

Solution Code

class Solution {
    public int minTimeToVisitAllPoints(int[][] points) {
        int minTime = 0;
        for (int i = 1; i < points.length; i++) {
            int xDiff = Math.abs(points[i][0] - points[i - 1][0]);
            int yDiff = Math.abs(points[i][1] - points[i - 1][1]);
            minTime += Math.max(xDiff, yDiff);
        }
        return minTime;
    }
}

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