LeetCode 1281: Subtract the Product and Sum of Digits of an Integer Solution
Master LeetCode problem 1281 (Subtract the Product and Sum of Digits of an Integer), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1281. Subtract the Product and Sum of Digits of an Integer
Problem Explanation
Explanation
To solve this problem, we will iterate through the digits of the given number, calculate the product and sum of the digits, and then find the difference between the product and sum. We can obtain the digits of the number by repeatedly dividing it by 10 and extracting the remainder.
- Time complexity: O(log10(n)) where n is the given number
- Space complexity: O(1)
Solution Code
class Solution {
public int subtractProductAndSum(int n) {
int product = 1, sum = 0;
while (n > 0) {
int digit = n % 10;
product *= digit;
sum += digit;
n /= 10;
}
return product - sum;
}
}Try It Yourself
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How to solve LeetCode 1281 (Subtract the Product and Sum of Digits of an Integer)?
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What is the time complexity of LeetCode 1281 (Subtract the Product and Sum of Digits of an Integer)?
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