LeetCode 1288: Remove Covered Intervals Solution

Master LeetCode problem 1288 (Remove Covered Intervals), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1288. Remove Covered Intervals

Medium

Array Sorting

Problem Explanation

Explanation

To solve this problem, we can sort the intervals based on the start point in ascending order. Then, we iterate over the sorted intervals and keep track of the current end point. If the current interval has an end point greater than the current end point, it means it is not covered by any previous interval, so we increment the count of remaining intervals.

Here is the step-by-step algorithm:

Sort the intervals based on the start point in ascending order.
Initialize a variable remainingIntervals to keep track of the count of remaining intervals.
Initialize a variable currentEnd to keep track of the current end point.
Iterate over the sorted intervals and check if the current interval's end point is greater than the current end point. If yes, increment remainingIntervals and update the currentEnd to the current interval's end point.

Time complexity: O(n log n) where n is the number of intervals due to sorting.
Space complexity: O(1)

Solution Code

class Solution {
    public int removeCoveredIntervals(int[][] intervals) {
        Arrays.sort(intervals, (a, b) -> a[0] == b[0] ? b[1] - a[1] : a[0] - b[0]);
        int remainingIntervals = 0;
        int currentEnd = 0;

        for (int[] interval : intervals) {
            if (interval[1] > currentEnd) {
                remainingIntervals++;
                currentEnd = interval[1];
            }
        }

        return remainingIntervals;
    }
}

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