LeetCode 1295: Find Numbers with Even Number of Digits Solution
Master LeetCode problem 1295 (Find Numbers with Even Number of Digits), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
Problem Explanation
Explanation
To solve this problem, we iterate through the array of numbers and count the number of digits in each number. If the count is even, we increment a counter. Finally, we return this counter as the result. The number of digits in a number can be calculated by taking the log base 10 of the number and adding 1 to it. We can then check if this count is even and update the counter accordingly.
- Time complexity: O(n) where n is the number of elements in the input array.
- Space complexity: O(1) as we are using a constant amount of extra space.
Solution Code
class Solution {
public int findNumbers(int[] nums) {
int count = 0;
for (int num : nums) {
int digits = (int) (Math.log10(num) + 1);
if (digits % 2 == 0) {
count++;
}
}
return count;
}
}Try It Yourself
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