LeetCode 1300: Sum of Mutated Array Closest to Target Solution

Master LeetCode problem 1300 (Sum of Mutated Array Closest to Target), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1300. Sum of Mutated Array Closest to Target

Medium

Array Binary Search Sorting

Problem Explanation

Explanation:

To solve this problem, we can use binary search to find the optimal integer value. We set the lower bound as 0 and the upper bound as the maximum value in the array. Then, we perform a binary search to find the value that minimizes the absolute difference between the sum of the mutated array and the target value.

Start by initializing the lower bound as 0 and the upper bound as the maximum value in the array.
Perform a binary search to find the optimal value that minimizes the absolute difference between the sum of the mutated array and the target value.
In each iteration of binary search, calculate the sum of the mutated array by replacing all values greater than the mid value with the mid value.
Update the lower or upper bound based on whether the calculated sum is less than or greater than the target value.
Return the closest integer value to the target.

Time complexity: O(n log(max(arr))) Space complexity: O(1)

Solution Code

class Solution {
    public int findBestValue(int[] arr, int target) {
        int left = 0, right = 0;
        for (int num : arr) {
            right = Math.max(right, num);
        }
        
        while (left < right) {
            int mid = left + (right - left) / 2;
            int sum = calculateSum(arr, mid);
            
            if (sum < target) {
                left = mid + 1;
            } else {
                right = mid;
            }
        }
        
        int sum1 = calculateSum(arr, left - 1);
        int sum2 = calculateSum(arr, left);
        
        return Math.abs(sum1 - target) <= Math.abs(sum2 - target) ? left - 1 : left;
    }
    
    private int calculateSum(int[] arr, int value) {
        int sum = 0;
        for (int num : arr) {
            sum += Math.min(num, value);
        }
        return sum;
    }
}

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