LeetCode 1308: Running Total for Different Genders Solution

Master LeetCode problem 1308 (Running Total for Different Genders), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1308. Running Total for Different Genders

Medium

Database

Problem Explanation

Explanation:

To solve this problem, we can iterate through the given list of transactions and maintain a running total for different genders separately. We can use a HashMap to keep track of the running total for each gender. Whenever we encounter a new transaction for a particular gender, we update the running total for that gender.

Algorithmic Idea:

Create a HashMap to store the running total for each gender.
Iterate through the list of transactions.
For each transaction, update the running total for the corresponding gender in the HashMap.
Calculate the running total for each gender at every step.

Time Complexity:

The time complexity of this approach is O(N), where N is the number of transactions in the input list.

Space Complexity:

The space complexity of this approach is O(N), where N is the number of unique genders in the input list.

Solution Code

import java.util.HashMap;
import java.util.List;
import java.util.Map;

class Solution {
    public int[] runningTotal(int[][] transactions) {
        Map<Integer, Integer> genderRunningTotal = new HashMap<>();
        List<Integer> result = new ArrayList<>();
        
        for (int[] transaction : transactions) {
            int gender = transaction[0];
            int amount = transaction[1];
            
            genderRunningTotal.put(gender, genderRunningTotal.getOrDefault(gender, 0) + amount);
            
            int runningTotalMale = genderRunningTotal.getOrDefault(0, 0);
            int runningTotalFemale = genderRunningTotal.getOrDefault(1, 0);
            
            result.add(runningTotalMale - runningTotalFemale);
        }
        
        return result.stream().mapToInt(Integer::intValue).toArray();
    }
}

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