LeetCode 1316: Distinct Echo Substrings Solution

Master LeetCode problem 1316 (Distinct Echo Substrings), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1316. Distinct Echo Substrings

Hard

String Trie Rolling Hash Hash Function

Problem Explanation

Explanation:

To solve this problem, we can iterate through all possible substrings of the given text and check if a substring can be formed by concatenating itself with another identical substring. We can achieve this by comparing the first half of the substring with the second half.

Algorithmic Idea:

Iterate through all possible substrings of the given text.
Check if a substring can be formed by concatenating itself with another identical substring.
Keep track of distinct substrings that satisfy the condition.
Return the count of distinct substrings.

Time Complexity:

The time complexity of this approach is O(n^3) where n is the length of the input text.

Space Complexity:

The space complexity of this approach is O(n) where n is the length of the input text.

Solution Code

class Solution {
    public int distinctEchoSubstrings(String text) {
        int n = text.length();
        Set<String> set = new HashSet<>();
        for (int i = 0; i < n; i++) {
            for (int j = i + 1; j < n; j += 2) {
                int len = j - i;
                if (j + len <= n && text.substring(i, i + len).equals(text.substring(j, j + len))) {
                    set.add(text.substring(i, i + len));
                }
            }
        }
        return set.size();
    }
}

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What is the time complexity of LeetCode 1316 (Distinct Echo Substrings)?

The time complexity for LeetCode 1316 (Distinct Echo Substrings) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

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