LeetCode 1336: Number of Transactions per Visit Solution
Master LeetCode problem 1336 (Number of Transactions per Visit), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1336. Number of Transactions per Visit
Problem Explanation
Explanation:
To solve this problem, we can use a dynamic programming approach. We can define a 2D array dp where dp[i][j] represents the maximum profit we can make up to visit j with i transactions. We can then iterate over the transactions and visits to fill in the dp array based on the following conditions:
- If we do not make a transaction at visit
j, thendp[i][j] = dp[i][j-1]since the profit remains the same. - If we make a transaction at visit
j, then we need to consider the maximum profit we can get by either selling at visitjor carrying over the profit from previous visits with one less transaction.
Finally, the answer will be the maximum profit we can make with the given number of transactions.
Time Complexity: O(transactions * visits) Space Complexity: O(transactions * visits)
: :
Solution Code
class Solution {
public int maxProfit(int[] visits, int transactions) {
int n = visits.length;
int[][] dp = new int[transactions + 1][n];
for (int i = 1; i <= transactions; i++) {
int maxDiff = -visits[0];
for (int j = 1; j < n; j++) {
dp[i][j] = Math.max(dp[i][j - 1], visits[j] + maxDiff);
maxDiff = Math.max(maxDiff, dp[i - 1][j] - visits[j]);
}
}
return dp[transactions][n - 1];
}
}Try It Yourself
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