LeetCode 1337: The K Weakest Rows in a Matrix Solution
Master LeetCode problem 1337 (The K Weakest Rows in a Matrix), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1337. The K Weakest Rows in a Matrix
Problem Explanation
Explanation
To solve this problem, we need to find the weakest rows based on the number of soldiers in each row. We can iterate over each row, count the number of soldiers, and store the counts along with the row indices. Then, we can sort these counts and indices based on the number of soldiers and return the first k indices.
- Create a list to store the counts and row indices.
- Iterate over each row in the matrix and count the number of soldiers.
- Store the count and row index in the list.
- Sort the list based on counts and return the first k row indices.
Time complexity: O(m * n + m * log(m)) where m is the number of rows and n is the number of columns in the matrix. Space complexity: O(m) for storing counts and indices.
Solution Code
class Solution {
public int[] kWeakestRows(int[][] mat, int k) {
int m = mat.length;
int n = mat[0].length;
int[] counts = new int[m];
for (int i = 0; i < m; i++) {
int count = 0;
for (int j = 0; j < n; j++) {
if (mat[i][j] == 1) {
count++;
} else {
break;
}
}
counts[i] = count * 1000 + i; // Using a number larger than m for sorting
}
Arrays.sort(counts);
int[] result = new int[k];
for (int i = 0; i < k; i++) {
result[i] = counts[i] % 1000;
}
return result;
}
}Try It Yourself
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