LeetCode 1344: Angle Between Hands of a Clock Solution
Master LeetCode problem 1344 (Angle Between Hands of a Clock), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1344. Angle Between Hands of a Clock
Problem Explanation
Explanation
To solve this problem, we need to calculate the angle between the hour and minute hands of a clock. The hour hand moves 360 degrees in 12 hours, which means it moves 30 degrees per hour or 0.5 degrees per minute. The minute hand moves 360 degrees in 60 minutes, which means it moves 6 degrees per minute. We calculate the angles made by the hour and minute hands from the 12 o'clock position, then find the absolute difference between these angles. The minimum angle between the two hands will be the smaller of the two angles or the absolute difference if they cross over each other.
Solution Code
class Solution {
public double angleClock(int hour, int minutes) {
double hourAngle = (hour % 12 + minutes / 60.0) * 30;
double minuteAngle = minutes * 6;
double angle = Math.abs(hourAngle - minuteAngle);
return Math.min(angle, 360 - angle);
}
}Try It Yourself
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