LeetCode 1350: Students With Invalid Departments Solution

Master LeetCode problem 1350 (Students With Invalid Departments), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1350. Students With Invalid Departments

Problem Explanation

Explanation

Given a list of students with their departments and a list of valid departments, we need to find and return a list of students who are in invalid departments.

To solve this problem, we can iterate through the list of students and for each student, check if their department is not in the list of valid departments. If the department is invalid, we add the student to the result list.

Algorithm

  1. Initialize an empty list result to store students with invalid departments.
  2. Iterate through each student in the input list.
  3. For each student, check if their department is not in the list of valid departments.
  4. If the department is not valid, add the student to the result list.
  5. Return the result list containing students with invalid departments.

Time Complexity

The time complexity of this algorithm is O(n), where n is the number of students in the input list.

Space Complexity

The space complexity is O(k), where k is the number of students with invalid departments.

Solution Code

import java.util.ArrayList;
import java.util.List;

class Solution {
    public List<String> getInvalidDepartments(List<List<String>> students, List<String> validDepartments) {
        List<String> result = new ArrayList<>();
        
        for (List<String> student : students) {
            String department = student.get(1);
            if (!validDepartments.contains(department)) {
                result.add(student.get(0));
            }
        }
        
        return result;
    }
}

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