LeetCode 1366: Rank Teams by Votes Solution
Master LeetCode problem 1366 (Rank Teams by Votes), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1366. Rank Teams by Votes
Problem Explanation
Explanation:
To solve this problem, we need to count the number of votes each team received for each rank and then sort the teams based on these counts. If there is a tie in the number of first-place votes, we move to the second-place votes, and so on until the tie is broken. If teams are still tied after considering all positions, we sort them alphabetically based on their team letter.
- Initialize a map to store the vote counts for each team at each rank.
- Iterate through the votes and update the counts in the map.
- Implement a custom comparator to sort the teams based on vote counts.
- Sort the teams using the custom comparator.
- Generate the final sorted string based on the sorted teams.
Time Complexity: The time complexity of this approach is O(n * m * log(m)), where n is the number of votes and m is the number of teams (26 in this case).
Space Complexity: The space complexity is O(m^2), where m is the number of teams.
:
Solution Code
class Solution {
public String rankTeams(String[] votes) {
int n = votes[0].length();
Map<Character, int[]> teamVotes = new HashMap<>();
for (String vote : votes) {
for (int i = 0; i < n; i++) {
char team = vote.charAt(i);
teamVotes.putIfAbsent(team, new int[n]);
teamVotes.get(team)[i]++;
}
}
List<Character> teams = new ArrayList<>(teamVotes.keySet());
Collections.sort(teams, (a, b) -> {
for (int i = 0; i < n; i++) {
if (teamVotes.get(a)[i] != teamVotes.get(b)[i]) {
return teamVotes.get(b)[i] - teamVotes.get(a)[i];
}
}
return a - b;
});
StringBuilder sb = new StringBuilder();
for (char team : teams) {
sb.append(team);
}
return sb.toString();
}
}Try It Yourself
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