LeetCode 1374: Generate a String With Characters That Have Odd Counts Solution
Master LeetCode problem 1374 (Generate a String With Characters That Have Odd Counts), a easy challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1374. Generate a String With Characters That Have Odd Counts
Problem Explanation
Explanation:
To generate a string with characters that have odd counts, we can create a string of length n by repeating any character an odd number of times. We can achieve this by using two different characters and repeating one of them (n-1) times and the other character once. This way, we ensure that each character appears an odd number of times in the final string.
:
Solution Code
class Solution {
public String generateTheString(int n) {
StringBuilder sb = new StringBuilder();
if (n % 2 == 0) {
sb.append('a');
n--;
}
for (int i = 0; i < n; i++) {
sb.append('b');
}
return sb.toString();
}
}Try It Yourself
Loading code editor...
Related LeetCode Problems
Frequently Asked Questions
How to solve LeetCode 1374 (Generate a String With Characters That Have Odd Counts)?
This page provides optimized solutions for LeetCode problem 1374 (Generate a String With Characters That Have Odd Counts) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.
What is the time complexity of LeetCode 1374 (Generate a String With Characters That Have Odd Counts)?
The time complexity for LeetCode 1374 (Generate a String With Characters That Have Odd Counts) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.
Can I run code for LeetCode 1374 on DevExCode?
Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 1374 in Java, C++, or Python.