LeetCode 1375: Number of Times Binary String Is Prefix-Aligned Solution
Master LeetCode problem 1375 (Number of Times Binary String Is Prefix-Aligned), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1375. Number of Times Binary String Is Prefix-Aligned
Problem Explanation
Explanation
To solve this problem, we can iterate through the flips array and keep track of the current prefix alignment status. We initialize a counter variable to count the number of times the binary string is prefix-aligned. For each flip, we update the prefix alignment status by checking if the flipped index is less than or equal to the current prefix length. If it is, we toggle the prefix alignment status. Finally, we return the count of prefix-aligned states.
- Time complexity: O(n) where n is the length of the flips array.
- Space complexity: O(1)
Solution Code
class Solution {
public int maxNumberOfFamilies(int n, int[] flips) {
int count = 0;
boolean aligned = false;
for (int flip : flips) {
if (flip <= 2) {
aligned = true;
}
if (flip >= 3 && flip <= 6) {
aligned = true;
}
if (flip >= 7 && flip <= 8) {
aligned = true;
}
if (flip >= 9 && flip <= 10) {
aligned = true;
}
if (flip >= 3 && flip <= 8) {
count++;
}
}
return count + (aligned ? 0 : n);
}
}Try It Yourself
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