LeetCode 1376: Time Needed to Inform All Employees Solution

Master LeetCode problem 1376 (Time Needed to Inform All Employees), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1376. Time Needed to Inform All Employees

Medium

Tree Depth-First Search Breadth-First Search

Problem Explanation

Explanation

To solve this problem, we can use a depth-first search (DFS) approach to traverse the tree structure of employees starting from the head of the company. We will keep track of the time needed to inform each employee along the way. The total time needed will be the maximum time taken among all employees to inform their subordinates.

Construct an adjacency list to represent the tree structure of employees.
Perform a DFS starting from the head of the company, updating the time needed to inform each employee based on their informTime and the time taken to inform their manager.
Keep track of the maximum time taken among all employees.

Time Complexity: O(N), where N is the number of employees. Space Complexity: O(N), for storing the adjacency list and auxiliary space for the DFS.

Solution Code

class Solution {
    public int numOfMinutes(int n, int headID, int[] manager, int[] informTime) {
        List<List<Integer>> adjList = new ArrayList<>();
        for (int i = 0; i < n; i++) {
            adjList.add(new ArrayList<>());
        }
        for (int i = 0; i < n; i++) {
            if (manager[i] != -1) {
                adjList.get(manager[i]).add(i);
            }
        }
        return dfs(adjList, informTime, headID);
    }
    
    private int dfs(List<List<Integer>> adjList, int[] informTime, int curr) {
        int time = 0;
        for (int sub : adjList.get(curr)) {
            time = Math.max(time, dfs(adjList, informTime, sub));
        }
        return informTime[curr] + time;
    }
}

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