LeetCode 1383: Maximum Performance of a Team Solution

Master LeetCode problem 1383 (Maximum Performance of a Team), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1383. Maximum Performance of a Team

Hard

Array Greedy Sorting Heap (Priority Queue)

Problem Explanation

Explanation

To solve this problem, we can sort the engineers by efficiency in descending order. Then, we iterate through each engineer starting from the most efficient one. For each engineer, we calculate the maximum performance that can be achieved by including this engineer and at most k - 1 engineers with higher efficiency. We keep track of the total speed of the selected engineers and the minimum efficiency encountered so far. At each step, we update the maximum performance if the current performance is greater.

By iterating through the engineers sorted by efficiency, we ensure that for each engineer we consider, we have already included the k - 1 most efficient engineers before them. This guarantees that we are selecting the most efficient team possible.

The algorithm has a time complexity of O(n log n) due to sorting the engineers by efficiency and a space complexity of O(n) to store the engineers.

Solution Code

class Solution {
    public int maxPerformance(int n, int[] speed, int[] efficiency, int k) {
        int[][] engineers = new int[n][2];
        for (int i = 0; i < n; i++) {
            engineers[i] = new int[]{efficiency[i], speed[i]};
        }
        Arrays.sort(engineers, (a, b) -> b[0] - a[0]);
        
        PriorityQueue<Integer> pq = new PriorityQueue<>(k, (a, b) -> a - b);
        long totalSpeed = 0, maxPerformance = 0;
        for (int[] engineer : engineers) {
            int currEfficiency = engineer[0];
            int currSpeed = engineer[1];
            
            pq.offer(currSpeed);
            totalSpeed += currSpeed;
            if (pq.size() > k) {
                totalSpeed -= pq.poll();
            }
            
            maxPerformance = Math.max(maxPerformance, totalSpeed * currEfficiency);
        }
        
        return (int) (maxPerformance % 1000000007);
    }
}

Try It Yourself

Loading code editor...

Frequently Asked Questions

How to solve LeetCode 1383 (Maximum Performance of a Team)?

This page provides optimized solutions for LeetCode problem 1383 (Maximum Performance of a Team) in Java, C++, and Python, along with a detailed explanation and an interactive code editor to test your code.

What is the time complexity of LeetCode 1383 (Maximum Performance of a Team)?

The time complexity for LeetCode 1383 (Maximum Performance of a Team) varies by solution. Check the detailed explanation section for specific complexities in Java, C++, and Python implementations.

Can I run code for LeetCode 1383 on DevExCode?

Yes, DevExCode provides an interactive code editor where you can write, test, and run your code for LeetCode 1383 in Java, C++, or Python.

Back to LeetCode Solutions