LeetCode 1400: Construct K Palindrome Strings Solution
Master LeetCode problem 1400 (Construct K Palindrome Strings), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1400. Construct K Palindrome Strings
Problem Explanation
Explanation:
To construct k palindrome strings using all characters in the input string s, we need to ensure that each character appears even number of times, or at most one character appears an odd number of times. This is because a palindrome can have at most one character with an odd frequency.
Therefore, we can count the frequency of each character in the input string s. Then, we iterate through the frequency count and check if the number of characters with odd frequency is less than or equal to k. If this condition is satisfied, we can construct k palindrome strings using all characters in s.
- Time complexity: O(n), where n is the length of the input string s.
- Space complexity: O(1) since the frequency map will have a fixed size of 26 characters for lowercase English letters.
Solution Code
class Solution {
public boolean canConstruct(String s, int k) {
if (s.length() < k) return false;
int[] freq = new int[26];
for (char c : s.toCharArray()) {
freq[c - 'a']++;
}
int oddCount = 0;
for (int f : freq) {
if (f % 2 == 1) {
oddCount++;
}
}
return oddCount <= k;
}
}Try It Yourself
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