LeetCode 1412: Find the Quiet Students in All Exams Solution
Master LeetCode problem 1412 (Find the Quiet Students in All Exams), a hard challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.
1412. Find the Quiet Students in All Exams
Problem Explanation
Explanation
To solve this problem, we need to find the students who always have a lower score than all of their immediate neighbors in all exams. We can iterate over the students and exams, comparing each student's scores with their neighbors to find the quiet students.
Algorithmic Idea
- Iterate over each student.
- For each student, compare their scores with the scores of the students before and after them.
- If the student's score is lower than both neighbors' scores for all exams, add the student to the list of quiet students.
Time Complexity
The time complexity of this solution is O(n*m), where n is the number of students and m is the number of exams.
Space Complexity
The space complexity is O(n), where n is the number of quiet students.
Solution Code
class Solution {
public List<Integer> quietStudents(int[][] exams) {
List<Integer> quietStudents = new ArrayList<>();
int n = exams.length;
int m = exams[0].length;
for (int i = 0; i < n; i++) {
boolean isQuiet = true;
for (int j = 0; j < m; j++) {
if ((i > 0 && exams[i][j] >= exams[i - 1][j]) ||
(i < n - 1 && exams[i][j] >= exams[i + 1][j])) {
isQuiet = false;
break;
}
}
if (isQuiet) {
quietStudents.add(i);
}
}
return quietStudents;
}
}Try It Yourself
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