1450. Number of Students Doing Homework at a Given Time
Explanation:
- Iterate through the startTime and endTime arrays simultaneously.
- For each student, check if the queryTime falls within the interval [startTime[i], endTime[i]].
- Increment a counter if the queryTime is within the interval.
- Return the final count as the number of students doing homework at the given queryTime.
Time Complexity: O(n) where n is the number of students
Space Complexity: O(1)
class Solution {
public int busyStudent(int[] startTime, int[] endTime, int queryTime) {
int count = 0;
for (int i = 0; i < startTime.length; i++) {
if (startTime[i] <= queryTime && queryTime <= endTime[i]) {
count++;
}
}
return count;
}
}Code Editor (Testing phase)
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