LeetCode 1465: Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts Solution

Master LeetCode problem 1465 (Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts), a medium challenge, with our optimized solutions in Java, C++, and Python. Explore detailed explanations, test your code in our interactive editor, and prepare for coding interviews.

1465. Maximum Area of a Piece of Cake After Horizontal and Vertical Cuts

Problem Explanation

Explanation:

To find the maximum area of a piece of cake after cutting it with horizontal and vertical cuts, we need to determine the maximum gap between consecutive horizontal cuts and vertical cuts. The maximum area will be the product of the maximum gap in horizontal cuts and vertical cuts.

  1. Sort the horizontalCuts and verticalCuts arrays.
  2. Determine the maximum gap between horizontal cuts and vertical cuts.
  3. Calculate the maximum area by multiplying the maximum horizontal gap and maximum vertical gap modulo 10^9 + 7.

Time Complexity: O(n log n) where n is the total number of cuts (horizontal + vertical). Space Complexity: O(1)

:

Solution Code

class Solution {
    public int maxArea(int h, int w, int[] horizontalCuts, int[] verticalCuts) {
        Arrays.sort(horizontalCuts);
        Arrays.sort(verticalCuts);
        
        long maxHorizontalGap = Math.max(horizontalCuts[0], h - horizontalCuts[horizontalCuts.length - 1]);
        long maxVerticalGap = Math.max(verticalCuts[0], w - verticalCuts[verticalCuts.length - 1]);
        
        for (int i = 1; i < horizontalCuts.length; i++) {
            maxHorizontalGap = Math.max(maxHorizontalGap, horizontalCuts[i] - horizontalCuts[i - 1]);
        }
        
        for (int i = 1; i < verticalCuts.length; i++) {
            maxVerticalGap = Math.max(maxVerticalGap, verticalCuts[i] - verticalCuts[i - 1]);
        }
        
        return (int)((maxHorizontalGap * maxVerticalGap) % 1000000007);
    }
}

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